The point of intersection of the lines represented by the equation $2 x^{2} + 3 y^{2} + 7 x y + 8 x + 14 y + 8 = 0$ is

(0, 2)

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(1, 2)

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(-2, 0)

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(-2, 1)

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Solution

The correct option is C
(-2, 0)

If the equation is general equation

$a x^{2} + 2 h x y + b y^{2} + 2 g x + 2 f y + c = 0$

Then points of intersection are given by $(\frac{h f - b g}{a b - h^{2}}, \frac{h g - a f}{a b - h^{2}})$

Hence point is (-2,0).

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