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Question

The point of intersection of the tangent x+3y=8 with the circle x2+y2=16 is

A
(22,22)
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B
(2,23)
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C
(23,2)
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D
(2,23)
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Solution

The correct option is B (2,23)
Point form of tangent to circle
xx1+yy1=16 (1)
Tangent to the circle is x+3y=8
Multiplying above equation by 2, we get
2x+23y=16 (2)
Comparing equation (1) and (2), we get
x1=2,y1=23

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