Question

The point of intersection of the tangents drawn to the curve $x^{2}y=1-y$ at the point where it is intersected by the curve xy$=1-y,$ is given by

• A. $(0,1)$
• B. $(1,1)$
• C. $(0,-1)$
• D. none of these

Answer 1

Answer: (A)

$(0,1)$

$pointofintersectionoftangents$

$tothecurvewillbetheintersectionpointofcurves.xy=1-yy=\frac{1}{1+x}anothercurve{x}^{2}y=1-y{x}^2.\frac{1}{1+x}=1-\frac{1}{1+x}\frac{x^2}{1+x}=\frac{x}{1+x}x=0soy=1.$