Question

The point of intersection of the tangents of the circle $x^2+y^2=10$, drawn at end points of the chord x + y = 2 is

• A. (–5, –5)
• B. (–5, –4)
• C. (–4, –5)
• D. None of these

Answer 1

The correct option is A

(–5, –5)

If you understood the question clearly we are actually asked to find the pole of the line x + y = 2 (which is polar) w.r.t then circle $x^2+y^2=10$.
We know how to find the equation of polar if co-ordinates of pole is given.
if $(x_1,y_1)$ are the coordinates of pole then equation of polar with respect to the circle $x^2+y^2=a^2$ will be -
$x.x_1+y.y_1=10$
$\frac{x.x_1+y.y_1}{5}=2$
On comparing we get co-odrinates of pole -
$(x_1,y_1)$ = (5,5)