The point of intersection of two lines $5 x - 3 y = 2$ and $2 x + y = 3$ is

(1, 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1, - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2, - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(1, 1)$
Given lines are: $5 x - 3 y = 2$ .... (1)
and $2 x + y = 3$ ... (2)
Multiply equation (2) with 3 and add with (1), we get
$5 x - 3 y + 3 (2 x + y) = 2 + 3 (3)$
$\Rightarrow 5 x - 3 y + 6 x + 3 y = 2 + 9$
$\Rightarrow 11 x = 11$
$\Rightarrow x = 1$
Now, put value of $x = 1$ in (1), we get
$5 (1) - 3 y = 2$
$\Rightarrow 5 - 3 y = 2$
$\Rightarrow - 3 y = - 3$
$\Rightarrow y = 1$
Hence, the point of intersection of two lines is $(1, 1) .$

Suggest Corrections

Similar questions

The point of intersection of the line $\frac{x}{1} = \frac{y - 1}{2} = \frac{z + 2}{3}$ and the plane $2 x + 3 y + z = 0$ is:

x - y = 1

2 x + 3 y = 4

(2, - 3)

(1, 1)

\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4}

4 x - 3 y + 1 = 0 = 5 x - 3 z + 2

(1, 3)

2 x - 3 y + 1 = 0

5 x + y - 3 = 0

Join BYJU'S Learning Program