The point on the curve y=x2+7x+2 closest to the line y=3x−3 is ⋯⋯
A
(−2,−8)
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B
(−8,−2)
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C
(2,8)
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D
(8,2)
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Solution
The correct option is A(−2,−8) Let P(x,y) be a point on the curve y=x2+7x+2 3x−3=x2+7x+2 f(x)=x2+4x+5 f′(x)=2x+4 For maxima or minima, f′(x)=0 ⇒x=−2 f′′(x)=2>0 Hence,f(x) has a minimum at x=−2 ⇒y=−8 Hence, the point is (-2,-8).