The point on the hyperbola x2−9y2=9, where the line 5x + 12y = 9 touches it, is .
A
(5,−43)
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B
(−5,43)
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C
(−53,4)
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D
(53,−4)
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Solution
The correct option is A(5,−43) Theequationofthelinewhichtouchesthehyperbolax2−9y2=9at(x1,y1)isx1x−9y1y=9orx19+(−y1)y=1Comparingitwiththe5x+12y=9or59x+43y=1wegetx19=59⇒x1=5−y1=43⇒y1=−43So,thepointis(5,−43)