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Question

The point on the line x21=y+32=z+52 at a distance of 6 from the point (2,3,5) is

A
(3,5,3)
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B
(4,7,9)
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C
(0,2,1)
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D
(3,5,3)
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Solution

The correct option is B (4,7,9)
Given, equation of line is
x21=y+32=z+52
DR's of given line is <1,2,2>
Then, DC's of given line is <13,23,23>
Thus, the given equation can be rewritten as
x213=y+323=z+523=r [say]
Any point on the line is (2+r3,32r3,52r3)
where, r=±6
Hence, points are (4,7,9) and (0,1,1).

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