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Question

The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) is

(a) 0,2 (b)(2,0) (c)(3,0) (d) (0,3)

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Solution

Let (−1,0) and (5,0) be equidistant from P (x,0)
(i.e) AP = BP
AP2=BP2
(i.e) (x+1)2+0=(x5)2+0

x2+2x+1=x210x+25
12x=24

x=2
Hence P is (2,0)

(b) (2,0) is correct answer


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