Question

The point on x-axis which is equidistant from points A(-1, 0) and B(5, 0) is

(a) 0,2 (b)(2,0) (c)(3,0) (d) (0,3)

Answer 1

Let (−1,0) and (5,0) be equidistant from P (x,0)
(i.e) AP = BP
⟹ $A{P}^2=B{P}^2$
(i.e) $(x+1{)}^2+0=(x-5{)}^2+0$

⟹ $x^2+2x+1=x^2-10x+25$
⟹$12x=24$

⟹$x=2$
Hence P is (2,0)

(b) (2,0) is correct answer