Question

The point on Y-axis equidistant from (–3, 4) and (7, 6) is ___.

• A. (0, 15)
• B. (0, 14)
• C. (0, 13)
• D. (15 , 0)

Answer 1

The correct option is A

(0, 15)

$\text{Any point on the y-axis has coordinates}\text{of the form}(0,y).\text{Since the point is equidistant from both}\text{points}(-3,4)\text{and}(7,6)\text{by distance formula,}{3}^2+{(y-4)}^2=7^2+{(y-6)}^{2}16–8y=40+36–12y4y=60y=15\therefore \text{the point is}(0,15).$