Question

The point on Y-axis equidistant from (–3, 4) and (7, 6) is ___.

• A. (0, 15)
• B. (15,0)
• C. (5,0)
• D. (0,5)

Answer 1

The correct option is A

(0, 15)

Any point on y-axis is of the form (0, y).
Since the point is equidistant from both points (-3,4) and (7,6),
$3^2+{(y-4)}^2=7^2+{(y-6)}^2\to 9+16–8y=49+36–12y\to 16–8y=40+36–12y\to 4y=60\to y=15$
Or, the point is (0, 15).