The point P(3,6) is first reflected on the line y=x and then the image point Q is again reflected on the line y=−x to get the image point Q′. Then the circumcentre of the △PQQ′ is
A
(6,3)
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B
(6,3)
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C
(3,−6)
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D
(0,0)
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Solution
The correct option is D(0,0) The point Q is the reflector of P and Q′ is the reflector of Q.
In △PQQ′ line y=x is perpendicular bisector of PQ and line y=−x is perpendicular bisector of QQ′. Both of these perpendicular bisectors of triangle are intersecting at point O(0,0). The point where two perpendicular bisectors of a triangle intersect is known as circumcenter. Hence, the circumcenter is O(0,0).