The point P (5, 3) was reflected in the origin to get the image P'.

(a) Write down the co-ordinates of P'.

(b) If M is the foot of the perpendicular from P to the x-axis, find the co-ordinates of M.

(c) If N is the foot of the perpendicular from P' to the x-axis, find the co-ordinates of N.

(d) Name the figure PMP'N.

(e) Find the area of the figure PMP'N.

Open in App

Solution

(a) Co-ordinates of P’ = (-5, -3)
(b) Co-ordinates of M = (5, 0)
(c) Co-ordinates of N = (-5, 0)
(d) PMP’N is a parallelogram.
(e) Are of PMP’N = 2 (Area of D PMN)
= 2 × ½ × 10 × 3
= 30 sq. units

Suggest Corrections

Similar questions

Q. Use graph paper for this question. The point

(5, 3)

was reflected in the origin to get the image

P^{'}

.
1. write down the coordinates of

p^{'}

.
2. If M is foot of perpendicular from

p

to x-axis, find the coordinates of

M

.
3. If

N

id the foot of perpendicular from

p^{'}

to the x-axis, find the coordinates of

N

.
4. Name the figure

P M P^{'} N

.
5. Find the area of the area

P M P^{'} N

The point P(5, 3) was reflected in the origin to get P'. If M is foot of the perpendicular from P to x -axis & N is foot of the perpendicular from P' to x -axis , Name the figure PMP'N

Q. The co-ordinates of the foot perpendicular from P(-3, 1) to X axis are .................

A point P (a, b) is reflected in the x-axis to P' (2, 3). Write down the values of a and b. P" is the image of P, reflected in the y-axis. Write down the co-ordinates of P". Find the co-ordinates of P", when P is reflected in the line, parallel to y-axis, such that x = 4.

(i) Point P (a, b) is reflected in the x-axis to P' (5, -2). Write down the values of a and b.

(ii) P" is the image of P when reflected in the y-axis. Write down the co-ordinates of P".

(iii) Name a single transformation that maps P' to P".

Join BYJU'S Learning Program

(a) Co-ordinates of P’ = (-5, -3) (b) Co-ordinates of M = (5, 0) (c) Co-ordinates of N = (-5, 0) (d) PMP’N is a parallelogram. (e) Are of PMP’N = 2 (Area of D PMN) = 2 × ½ × 10 × 3 = 30 sq. units

(a) Co-ordinates of P’ = (-5, -3)
(b) Co-ordinates of M = (5, 0)
(c) Co-ordinates of N = (-5, 0)
(d) PMP’N is a parallelogram.
(e) Are of PMP’N = 2 (Area of D PMN)
= 2 × ½ × 10 × 3
= 30 sq. units