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Question

The point which is equidistant from the points (a,0,0),(0,b,0),(0,0,c) and (0,0,0) is:

A
(a,b,c)
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B
(a,b,c)
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C
(2a,2b,2c)
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D
(a2,b2,c2)
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Solution

The correct option is D (a2,b2,c2)
Let the point (x,y,z) be the equidistant from (a,0,0),(0,b,0),(0,0,c) and (0,0,0).
(xa)2+(y0)2+(z0)2=(x0)2+(yb)2+(z0)2
=(x0)2+(y0)2+(zc)2=(x0)2+(y0)2+(z0)2
Solving above equations, we get x=a2,y=b2,z=c2

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