Question

The point which lies in the perpendicular bisector of the line segment joining the points A (-2, -5) and B (2,5) is

• A. (0, 0)
• B. (0, 2)
• C. (2, 0)
• D. (-2, 0)

Answer 1

The correct option is A (0, 0)

A perpendicular bisector of a line segment, passed through its midpoint.
If C is the point on AB, through which its perpendicular bisector passes, then C $=$ mid point of AB.
Mid
point of two points ${(x}_1,y_1)$ and ${(x}_2,y_2)$ is calculated by the formula $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$
Using this formula,
mid point of AB $=(\frac{-2+2}{2},\frac{-5+5}{2})=(0,0)$