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Byju's Answer
Standard XII
Mathematics
Bisectors of Angle between Two Lines
The point x...
Question
The point
(
x
1
,
y
1
)
,
(
x
2
,
y
2
)
,
(
x
1
,
y
2
)
&
(
x
2
,
y
1
)
are always
A
Collinear
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B
Concyclic
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C
Vertices of a square
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D
Vertices of a rhombus.
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Solution
The correct option is
B
Concyclic
Let the coordinates be denoted as
A
(
x
1
,
y
2
)
,
B
(
x
2
,
y
2
)
,
C
(
x
2
,
y
1
)
and
D
(
x
1
,
y
1
)
Plot the given points on a graph as above,
It is not necessary that
|
x
2
−
x
1
|
=
|
y
2
−
y
1
|
With
(
x
2
,
y
1
)
and
(
x
1
,
y
2
)
as ends of diameter
∠
A
B
C
=
90
∘
and
∠
A
D
C
=
90
∘
∴
A
B
C
D
are concyclic.
So,
B
is the correct option.
Suggest Corrections
0
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