The pointer of a picker wheel moves from AB and covers 45 parts of a circle- If the new position of the pointer is AB- what will the measure of angle BAB- be-

Fraction of distance the pointer moved nbsp; = 45 nbsp; Let’s write it as an equivalent fraction with 360^∘ nbsp; as the denominator. nbsp; 45=4×725× 72 ...

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The pointer of a picker wheel moves from $A B$ and covers $\frac{4}{5}$ parts of a circle. If the new position of the pointer is $A B^{'}$ , what will the measure of angle $B A B^{'}$ be?

90^{\circ}

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45^{\circ}

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288^{\circ}

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120^{\circ}

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Solution

The correct option is C $288^{\circ}$
Fraction of distance the pointer moved $= \frac{4}{5}$
Let’s write it as an equivalent fraction with $360^{\circ}$ as the denominator.
$\frac{4}{5} = \frac{4 \times 72}{5 \times 72} = \frac{288}{360}$

$\frac{288}{360}$ parts of the circle in degrees $= 288^{\circ}$
Therefore, measure of angle $B A B^{'} = 288^{\circ}$

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The pointer of a picker wheel moves from AB and covers 45 parts of a circle. If the new position of the pointer is AB′, what will the measure of angle BAB′ be?

The correct option is C 288∘Fraction of distance the pointer moved =45 Let’s write it as an equivalent fraction with 360∘ as the denominator. 45=4×725×72=288360 288360 parts of the circle in degrees =288∘ Therefore, measure of angle BAB′=288∘

The pointer of a picker wheel moves from $A B$ and covers $\frac{4}{5}$ parts of a circle. If the new position of the pointer is $A B^{'}$ , what will the measure of angle $B A B^{'}$ be?