The points (0, 8/3), (1, 3) and (82, 30) are the vertices of :

obtuse angled triangle

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right angled triangle

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isosceles triangle

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None of these

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Solution

The correct option is D None of these
Let, $P = (0, \frac{8}{3}), Q = (1, 3), R = (82, 30)$
Now, m1 $=$ slope of PQ $= \frac{3 \frac{8}{3}}{10} = \frac{1}{3}$
m2 $=$ slope of QR $= \frac{303}{821} = \frac{1}{3}$
Since, $m 1 = m 2$ , the three points P, Q, R are collinear

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