The points (0,1) (2,7) (-2,-7) (-1,-4) all fall on the line y = 3x + 1
False
Putting x = 0, y = 1 in y = 3x + 1
⟹1=(3x0)+1
Equation is satisfied. Hence, (0, 1) is on the line.
Putting x = 2, y = 7 in y = 3x + 1
⟹7=(3×2)+1
Equation is satisfied. Hence, (2, 7) is on the line.
Putting x = -2, y = -7 in y = 3x + 1
⟹−7≠(3×(−2))+1
Equation is not satisfied. Hence, (-2, -7) is not on the line.
Putting x = -1, y = -4 in y = 3x + 1
⟹−4≠(3×(−1))+1
Equation is not satisfied. Hence, (-1, -4) is not on the line.