The points (-2,10), (-2,2), and (6,2) are the vertices of

An equilateral triangle

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A right-angled isosceles triangle

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A scalene triangle

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An obtuse triangle

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Solution

The correct option is B A right-angled isosceles triangle
$A = (- 2, 10), B = (- 2, 2), C = (6, 2)$
AB = $\sqrt{{(- 2 + 2)}^{2} + {(10 - 2)}^{2}} = 8$
BC = $\sqrt{{(- 2 - 6)}^{2} + {(2 - 2)}^{2}} = 8$
AC = $\sqrt{{(- 2 - 6)}^{2} + {(10 - 2)}^{2}} = \sqrt{128}$
Here AB = BC and $A B^{2} + B C^{2} = A C^{2}$

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The points (-2,10), (-2,2), and (6,2) are the vertices of

The correct option is B A right-angled isosceles triangleA=(−2,10),B=(−2,2),C=(6,2)AB = √(−2+2)2+(10−2)2=8BC = √(−2−6)2+(2−2)2=8AC = √(−2−6)2+(10−2)2=√128Here AB = BC and AB2+BC2=AC2