The points (2,3) lies on the graph of the linear equation 3x−(a−1)y=2a−1. If the same point also liner the graph of the linear equation 5x+(1−2a)y=3b, then find the value of b
A
14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
13
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D13 It is given that (2,3) lies on the graph of the linear equation 3x−(a−1)y=2a−1
so, putting the value of x=2,y=3 we get
3×2−(a−1)×3=2a−1⇒6−3a+3=2a−1⇒−5a=−10⇒a=2
again (2,3) lies on the graph of the equation 5x+(1−2a)y=3b