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B
an isosceles triangle
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C
a right angled triangle
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D
an equilateral triangle
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Solution
The correct option is A a straight line. Given: Points (−2,3,5),(1,2,3) and (7,0,−1)
Let the points be P,Q and R respectively.
Applying Distance formula =√(x2−x1)2+(y2−y1)2+(z2−z1)2 PQ=√(1+2)2+(2−3)2+(3−5)2=√14 QR=√36+4+16=√56=2√14 PR=√(7+2)2+(0−3)2+36=√126=3√14
For triangle to form sum of any two sides > third side But,
Clearly, PQ+QR=PR Hence P,Q,R are collinear points.