The points A(−2,3,5),B(1,2,3)andC(7,0,−1) are _____
Collinear
Let A≡ (−2,3,5)
B≡ (1,2,3)
C≡ (7,0,−1)
AB = √(1+2)2 + (2−3)2 + (3−5)2 = √9+1+4 = √14
BC = √(7−1)2 + (0−2)2 + (−1−3)2 = √36+4+16 = 2√14
AC = √(7+2)2 + (0−3)2 + (−1−5)2 = √81+9+36 = 3√14
Thus AB+BC=Ac
Hence points A,B,C are collinear and B lies between A & C