The points A (2, 3), B(3, 5) and C (–1, –1) are the vertices of the triangle ABC. Find the equation of the altitude of the triangle through A.

13 = 2x + 3y

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17 = x + 3y

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20 = 2x + 5y

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13 = x + 3y

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Solution

The correct option is
A

13 = 2x + 3y
Given,
Vertices of the triangle $A B C$ are-
$A (2, 3), B (3, 5), C (- 1, - 1)$
Let, $(x_{1}, y_{1}) = (3, 5), (x_{2}, y_{2}) = (- 1, - 1)$
$∵$ Slope of BC $= \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$
And slope of $A D = \frac{- 1}{Slope of AB}$

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