Question

The points $A(0,0),B(3,4)$ and $C(6,8)$ are collinear, such that $2AB=AC$.

• A. True
• B. False

Answer 1

The correct option is A True

Given:

$A(0,0);B(3,4);C(6,8)$

Using distance formula:

$AB=\sqrt{(3-0{)}^2+(4-0{)}^2}=\sqrt{25}=5$

$AC=\sqrt{(6-0{)}^2+(8-0{)}^2}=\sqrt{100}=10$

Hence,

$\frac{AC}{AB}=\frac{10}{5}=2$

$⟹AC=2AB$