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Question

The points at which the function f(x)=x+1x2+x12 is discontinuous, are

A
–3, 4
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B
3, –4
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C
–1,–3, 4
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D
–1, 3, 4
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Solution

The correct option is B 3, –4

f(x)=x+1(x3)(x+4) is discontinuous if

(x−3)(x+4)=0(x-3)(x+4)=0(x3)(x+4)=0

x=3,x=−4x=3,x=-4x=3,x=4

at x=3 at x=3at x=3 , f(x)=

and at x=−4, f(x)=∞ at x=-4 , f(x)=\infty at x=4, f(x)=

Hence, given function is not contentious at points 3,4.


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