The points at which the function f(x)=x+1x2+x−12 is discontinuous, are
The correct option is B 3, –4
f(x)=x+1(x−3)(x+4) is discontinuous if
(x−3)(x+4)=0(x-3)(x+4)=0(x−3)(x+4)=0
x=3,x=−4x=3,x=-4x=3,x=−4
at x=3 at x=3at x=3 , f(x)=∞
and at x=−4, f(x)=∞ at x=-4 , f(x)=\infty at x=−4, f(x)=∞
Hence, given function is not contentious at points 3,−4.