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Question

The points E(6,4) and F(14,12) lie in the standard (x,y) coordinate plane shown below. Point D lies on ¯¯¯¯¯¯¯¯EF between E and F such that the length of ¯¯¯¯¯¯¯¯EF is 4 times the length of ¯¯¯¯¯¯¯¯¯DE. What are the coordinates of D?
500778.jpg

A
(7,5)
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B
(8,6)
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C
(8,8)
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D
(10,8)
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E
(12,10)
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Solution

The correct option is B (8,6)

Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then

(x,y)=(mx2+nx1m+n,my2+ny1m+n)

From the given condition we find that DE:EF=1:3. Let the coordinate of D be (x,y). Then
D(x,y)=(1(14)+3(6)4,1(12)+3(4)4)=(324,244)=(8,6)

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