Question

The points $(0,\frac{8}{3})$, (1, 3) and (82, 30) are vertices of -

• A. an obtuse angled triangle
• B. an acute angled triangle
• C. a right angled triangle
• D. an isosceles triangle

Answer 1

The correct option is B an acute angled triangle

$\Rightarrow (0,\frac{8}{3})(1,3)(82,30)$

Square of one side : $a^2=\{{(0-1)}^2+{(\frac{\infty }{3}-3)}^2\}$

= $\frac{10}{9}\simeq 1.11$

$b^2={(82-1)}^2+{(30-3)}^2=7290$

$c^2={(82-0)}^2+{(30-\frac{8}{3})}^2=7471.11$

it shows, $c^2>a^2+b^2$

so the $△$ would be acute.