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B
2nπ,n∈I
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C
(2n+1)π2,n∈I
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D
None of the above
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Solution
The correct option is C(2n+1)π2,n∈I Let f(x)=tanx The points of discontinuity of f(x) are those points where tanx is infinite. This gives tanx=∞ ie tanx=tanπ2 x=(2n+1)π2,n∈I