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Question

The points of discontinuity of tanx are

A
nπ,nI
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B
2nπ,nI
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C
(2n+1)π2,nI
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D
None of the above
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Solution

The correct option is C (2n+1)π2,nI
Let f(x)=tanx
The points of discontinuity of f(x) are those points where tanx is infinite. This gives
tanx=
ie tanx=tanπ2
x=(2n+1)π2,nI

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