The points of extremum of the function F x -1 x e - t 2 - 21- t 2 dt areA- - 1B- - 1 - 2C- - 2D- 0

The correct option is A ±1f'(x) = e^ x^2/2 (1 x^2) =0 ∴ x = ± 1 ...

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Extrema

The points of...

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The points of extremum of the function $F (x) = \int_{1}^{x} e^{- t^{2} / 2} (1 - t^{2})$ dt are

±1

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±1/2

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±2

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ϕ (x) = \int_{1}^{x} e^{- \frac{t^{2}}{2}} (1 - t^{2}) d t

The points of extremum of the function $F (x) = \int_{1}^{x} e^{- t^{2} / 2} (1 - t^{2})$ dt are

F (x) = \int_{1}^{x} e^{- t^{2 / 2}} (1 - t^{2}) d t

The function $f (x) = 2 x^{3} - 3 x^{2} - 12 x + 8$ has maximum at x =

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