The points of intersection of the line $4 x - 3 y - 10 = 0$ and the circle $x^{2} + y^{2} - 2 x + 4 y - 20 = 0$ are...................and....................

(4, 2)

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(- 2, - 6)

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(2, 2)

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(- 2, - 4)

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Solution

The correct options are
B $(- 2, - 6)$
D $(4, 2)$
Solve the two equations; the points are (4,2) and (-2,-6).

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and through the point

(- 1, 2)

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The points of intersection of the line 4x−3y−10=0 and the circle x2+y2−2x+4y−20=0 are...................and....................

The correct options are B (−2,−6) D (4,2)Solve the two equations; the points are (4,2) and (-2,-6).

The points of intersection of the line $4 x - 3 y - 10 = 0$ and the circle $x^{2} + y^{2} - 2 x + 4 y - 20 = 0$ are...................and....................

The correct options are
B $(- 2, - 6)$
D $(4, 2)$
Solve the two equations; the points are (4,2) and (-2,-6).