The points with position vectors 60^i+3^j,40^i−8^j and a^i−52^j are collinear, then the value of a is
A
−40
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B
10
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C
20
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D
−30
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Solution
The correct option is A−40 Let P,Q and R be the collinear points with position vectors 60^i+3^j,40^i−8^j and a^i−52^j respectively.
Then −−→PQ=λ−−→QR, for some scalar λ ⇒−20^i−11^j=λ((a−40)^i−44^j) ⇒λ(a−40)=−20 and −44λ=−11
Hence we have λ=14 and a=−40