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Question

The polar equation of the conic having latus rectum 12 and eccentricity 23 is

A
r(3+3cosθ)=20
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B
r(3+2cosθ)=18
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C
r(2+3cosθ)=18
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D
r(1+5cosθ)=18
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Solution

The correct option is D r(3+2cosθ)=18
Given latus rectum =12l=6 and e=23
Thus required conic is,
lr=1+ecosθ
r(2+3cosθ)=18

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