The polar equation of $x^{2} + y^{2} = 6 x$ is

r = 3 cos θ

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r = 6 sin θ

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r = 6 cos θ

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r = 3 sin θ

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Solution

The correct option is C $r = 6 cos θ$
Given, $x^{2} + y^{2} = 6 x$
Put $x = r cos θ, y = r sin θ$
Therefore, $r^{2} ({cos}^{2} θ + {sin}^{2} θ) = 6 r cos θ$
$\Rightarrow r = 6 cos θ$

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