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Eccentricity

The polar for...

Question

The polar form of the equation $x^{2} + y^{2} = a x$ is

r = a sin θ

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r = a cos θ

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r = - a sin θ

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none of these

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Solution

The correct option is D $r = a cos θ$
Given $x^{2} + y^{2} = a x$
$r^{2} - a r cos θ = 0$
$r (r - a cos θ) = 0$
$\Rightarrow r - a cos θ = 0$
$\Rightarrow r = a cos θ$

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Similar questions

What is the corresponding point of $(a c o s θ, b s i n θ)$ of $\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$ on its auxiliary cirlcle?

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