Question

The polar of point (2t,t-4)w.r.t the circle,x*2+y*2-4x-6y+1=0 passes through the point

Answer 1

This can be found by the formula T = 0

Given equation is x2+y2−4x−6y+1=0

i.e., (2t)x+(t-4)y− 2(x+2t)−3(y+(t-4))+1=0


2tx + ty - 4y - 2x - 4t - 3y - 3t + 12 + 1 = 0

(2t-2)x- (7-t) y - 7 t + 13 =0


(2t-2)x- (7-t) y = 7 t - 13