Question

The polar of the focus of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

• A. $x=\frac{a}{e}$
• B. $\frac{xa}{e}=1$
• C. $y=0$
• D. $x=\frac{b}{e}$

Answer 1

The correct option is A $x=\frac{a}{e}$

$\frac{x{x}_1}{a^2}-\frac{y{y}_1}{b^2}=1$ is the equation of polar, where $(x_1,y_1)$ is the pole.

so focus is $(ae,0)$, simply put we get

$\frac{aex}{a^2}$=1

$x=\frac{a}{e}$ is polar of the given hyperbola