The polar plot of the transfer function Gs - 10s-1s-10 for 0- will be in the

G(s) = 10(s+1)(s+10) For ω =0 ⇒ M_1= 1 and ϕ = 0^∘ ω = ∞⇒ M_2= 10 and ϕ _2 = tan^ 1∞+tan^ 1∞ = 0^∘ ∴ Polar plot As the zero is nearer to the imaginary axis ...

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Standard XII

Physics

Net Force

The polar plo...

Question

The polar plot of the transfer function $G (s) = \frac{10 (s + 1)}{s + 10} f o r 0 \leq ω \leq \infty$ will be in the

first quadrant

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second quadrant

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third quadrant

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fourth quadrant

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Solution

The correct option is A first quadrant
$G (s) = \frac{10 (s + 1)}{(s + 10)}$
For
$ω = 0 \Rightarrow M_{1} = 1 a n d ϕ = 0^{\circ}$
$ω = \infty \Rightarrow M_{2} = 10$
and $ϕ_{2} = - {tan}^{- 1} \infty + {tan}^{- 1} \infty = 0^{\circ}$
$∴$ Polar plot

As the zero is nearer to the imaginary axis hence the direction of polar plot is clockwise.

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The polar plot of the transfer function G(s)=10(s+1)s+10 for 0≤ω≤∞ will be in the

The correct option is A first quadrantG(s)=10(s+1)(s+10) For ω=0⇒M1=1 and ϕ=0∘ ω=∞⇒M2=10 and ϕ2=−tan−1∞+tan−1∞=0∘ ∴ Polar plot As the zero is nearer to the imaginary axis hence the direction of polar plot is clockwise.

The polar plot of the transfer function $G (s) = \frac{10 (s + 1)}{s + 10} f o r 0 \leq ω \leq \infty$ will be in the