The polarization of a wave with electric field vector E-E0ei- t- zax-ay is

Ans : (a) E = E_0e^i(ω t β z)(a_x+a⃗_⃗y⃗) E = E_0e^i(ω t β z)a_x+E_0e^i(ω t β z)a_y E= E_xa_x+E_ya_y So, E_x= E_0e^(ω t β z) E_y= E_0e^(ω t β z) E_x=E_y a ...

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Linear Polarization

The polarizat...

Question

The polarization of a wave with electric field vector $\to E = E_{0} e^{i^{(ω t - β z)}} (_{x} +_{y})$ is

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Solution

Ans : (a)

$E = E_{0} e^{i (ω t - β z)} (_{x} +_{y})$

$E = E_{0} e^{i (ω t - β z)}_{x} + E_{0} e^{i (ω t - β z)}_{y}$

$\to E = E_{x}_{x} + E_{y}_{y}$

So, $_{x} = E_{0} e^{(ω t - β z)}$

$_{y} = E_{0} e^{(ω t - β z)}$

$_{x} =_{y}$ at any time t

So, the polarization of the wave is linear.

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The polarization of a wave with electric field vector →E=E0ei(ωt−βz)(→ax+→ay) is

Ans : (a) E=E0ei(ωt−βz)(→ax+→ay) E=E0ei(ωt−βz)→ax+E0ei(ωt−βz)→ay →E=Ex→ax+Ey→ay So, −→Ex=E0e(ωt−βz) −→Ey=E0e(ωt−βz) −→Ex=−→Ey at any time t So, the polarization of the wave is linear.

The polarization of a wave with electric field vector $\to E = E_{0} e^{i^{(ω t - β z)}} (_{x} +_{y})$ is