The polynomial P(x)=4x3+7x2–5x+t, when divided by x+1 gives 3 as the remainder. Find the value of ‘t’.
-3
-4
-5
-6
The remainder when P(x) is divided by x+1 is 3, ⇒P(−1)=3 ⇒4×(−1)3+7×(−1)2−5x(−1)+t=3 ⇒4×−1+7×1+5+t=3 ⇒−4+7+5+t=3 ⇒8+t=3 ⇒t=−5
Statement1: The polynomial P(x)=4x3–3x2+5x–6 when divided by x–1 gives zero as the remainder.
Statement2: (x–1) is a factor of the polynomial P(x)=4x3–3x2+5x–6.
The remainder when the polynomial p(x)= x3 – 3x2 + 2x – 1 is divided by x-2 is