Question

The polynomial p(x) = kx³ +9x² +4x-8 when divided by [x+3] leaves a remainder 10(1-k). find the value of k.

Answer 1

P(x)=kx^3+9x^2+4x-8

g(x)= x+3

x+3=0

x= -3

Then p(-3)=remainder
As p(x) divided by x+3 leaves the remainder
10-10k

=>p(-3) =Remainder
-27K+81-12-8=10-10k

= -17k+51=0

k= -51/ -17

k=3