The polynomials ax3+3x2−13 and 2x3−5x+a are divided by x+2 if the remainder in each case is the same, find the value of a.
A
19
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B
14
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C
59
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D
45
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Solution
The correct option is A59 p(x)=ax3+3x2−13 and q(x)=2x3−5x+a When p(x) and q(x) are divided by x+2=0⇒x=−2 p(−2)=q(−2)⇒a(−2)3+3(−2)2−13=2(−2)3−5(−2)+a ⇒−8a+12−13=−16+10+a ⇒−9a=−5⇒a=59