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Question

The polynomials ax3+3x213 and 2x35x+a are divided by x+2 if the remainder in each case is the same, find the value of a.

A
19
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B
14
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C
59
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D
45
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Solution

The correct option is A 59
p(x)=ax3+3x213 and q(x)=2x35x+a
When p(x) and q(x) are divided by x+2=0x=2
p(2)=q(2)a(2)3+3(2)213=2(2)35(2)+a
8a+1213=16+10+a
9a=5a=59

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