The polynomials axax3- 3x2+4 and 2x3-5x+a when divided by x-2 leave the remainder p and q respectively.If p-2q=4 , find a
p(x)=ax^3-3x^2+4
g(x)=2x^3-5x+a ..
factor of g(x) and p(x) are x-2
p(2)= 8a-12+4=p [Remainder thm.]
= 8a-8=p
g(2)=16-10+a=q
=6+a=q
p-2q=4
8a-8-2(6+a)=4
8a-8-12-2a=4
6a-20=4
6a=24
a=24/6=4
Like if satisfied