The population of a city grows by 10% in first two years, decreases by 10% in the next one year and again increases by 10% in the next two years. If the original count of the population is 70000, what is the population count at the end of 5 years(approximately)?

92249

No worries! We‘ve got your back. Try BYJU‘S free classes today!

92268

No worries! We‘ve got your back. Try BYJU‘S free classes today!

92238

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

92248

No worries! We‘ve got your back. Try BYJU‘S free classes today!

92256

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
92238

Population after 5 years $= 70000 \times {(\frac{11}{10})}^{2} \times (\frac{9}{10}) \times {(\frac{11}{10})}^{2} = 92238$

Suggest Corrections

Similar questions

The population of a city increases by 10% every 5 years. If the population of the city in the year 1990 is 1,34,310. What was the population in the year 1980?

Q. In one year, the population of a village increased by 10% and on the next year, it decreased by 10%. If the end of the 2nd year, the population was 7920, what was it in the beginning?

Q. The present population of a city is 8000 if it increases by

10 %

during the first year and by

20 %

during the second year , then population after two years will be

Q. During one year, the population of a town increased by

5 %

and during the next year, the population decreased by

5 %

. If the total population is

9975

at the end of the second year, then what was the population size in the beginning of the first year?

The population of a certain city was 72000 on the last day of the year 1998. During next year it increased by $7 %$ but due to an epidemic it decreased by $10 %$ in the following year. What was its population at the end of the year 2000?

Join BYJU'S Learning Program

The population of a city grows by 10% in first two years, decreases by 10% in the next one year and again increases by 10% in the next two years. If the original count of the population is 70000, what is the population count at the end of 5 years(approximately)?

The correct option is C 92238 Population after 5 years =70000×(1110)2×(910)×(1110)2 = 92238

The correct option is C
92238

Population after 5 years $= 70000 \times {(\frac{11}{10})}^{2} \times (\frac{9}{10}) \times {(\frac{11}{10})}^{2} = 92238$