The population of a city in the year 2000 was 82,300. If average percent increase in population per decade is 35%, the population of the city in the year 2020 estimated geometrical increase will nearly be

100000

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150000

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175000

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125000

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Solution

The correct option is B 150000
Estimate of the population by geometrical increase method

$P_{n} = P_{0} {(1 + \frac{r}{100})}^{n}$

$P_{2020} = P_{2000} {(1 + \frac{35}{100})}^{2}$

$w h e r e, P_{0} = 82300, n = 2, r = 35 %$

$= 82300 {(1 + \frac{35}{100})}^{2}$

$= 149991. 75 ≃ 1, 50, 000$

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The population of a city in the year 2000 was 82,300. If average percent increase in population per decade is 35%, the population of the city in the year 2020 estimated geometrical increase will nearly be

The correct option is B 150000Estimate of the population by geometrical increase method Pn=P0(1+r100)n P2020=P2000(1+35100)2 where, P0=82300, n=2, r=35% =82300(1+35100)2 =149991.75≃1,50,000

The correct option is B 150000
Estimate of the population by geometrical increase method

$P_{n} = P_{0} {(1 + \frac{r}{100})}^{n}$

$P_{2020} = P_{2000} {(1 + \frac{35}{100})}^{2}$

$w h e r e, P_{0} = 82300, n = 2, r = 35 %$

$= 82300 {(1 + \frac{35}{100})}^{2}$

$= 149991. 75 ≃ 1, 50, 000$