The population of a city increased by approximately 20% this year.If the present population is 96000,calculate the population of the city last year.

Open in App

Solution

Dear student
$G i v e n : T h e p r e s e n t p o p u l a t i o n i s 96000 . L e t t h e l a s t y e a r' s p o p u l a t i o n b e x T h e n A T Q, x + 20 % o f x = 96000 \Rightarrow x + \frac{20}{100} x = 96000 \Rightarrow \frac{120 x}{100} = 96000 \Rightarrow x = \frac{96000 \times 100}{120} \Rightarrow x = 80000 S o, l a s t y e a r' s p o p u l a t i o n i s 80000$
Regards

Suggest Corrections

Similar questions

The population of city increases by

30

every year .If the present population is

33800

,then what was the population of the city two years ago?

Q. The population of a city increases by 30% every year. If the present population is 338000, then what was the population of the city 2 years ago?

City A has a population of 148000 which is decreasing at the rate of 2300 per year. City B has a population of 96000 which is increasing at the rate of 1700 per year. In how many years will the population of two cities become equal?

Q. The population of city increases at rate proportional to the population at that time if the population of city increases from 20 lacks, the population after 15 years.

Q. The present population of a city is 8000 if it increases by

10 %

during the first year and by

20 %

during the second year , then population after two years will be

Join BYJU'S Learning Program

The population of a city increased by approximately 20% this year.If the present population is 96000,calculate the population of the city last year.

Dear student Given: The present population is 96000.Let the last year's population be xThen ATQ,x+20% of x=96000⇒x+20100x=96000⇒120x100=96000⇒x=96000×100120⇒x=80000So, last year's population is 80000 Regards