The population of a city increases by 30% every year. If the present population is 338000, then what was the population of the city 2 years ago?

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Solution

Let the polulation a year ago be x

So, x+ 30x/100 = 338000 [30% increase means x + 30x/100]

130x/100= 338000

X = 338000 x 100/ 130

X= 260000

Let y be the polulation 2 years back

Y + 30y/100 = 260000

130y/100 = 260000

Y = 260000 x 100/ 130

Y= 200000

population of the city 2 years ago = 200000

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The population of a city increases by 30% every year. If the present population is 338000, then what was the population of the city 2 years ago?

Let the polulation a year ago be x So, x+ 30x/100 = 338000 [30% increase means x + 30x/100] 130x/100= 338000 X = 338000 x 100/ 130 X= 260000 Let y be the polulation 2 years back Y + 30y/100 = 260000 130y/100 = 260000 Y = 260000 x 100/ 130 Y= 200000 population of the city 2 years ago = 200000