Question

The population of a city increases each year by $4\%$ of what it had been at the beginning of each year. If its present population is $6760000$, find: Its population $2$ years hence is approx $7058522$.

• A. True
• B. False

Answer 1

The correct option is B False

Current Population$=6760000$ , R$=4\%$

After $1$ year

Population$=6760000+\frac{4}{100}\times 6760000=7030400$

After $2$ years

Population$=7030400+\frac{4}{100}\times 7030400=7311616$

Since the population of the city is not $7058522$ after $2$ years, therefore the statement is false