Question

The population of a city was $1,50,000$ in the year $2006$. It increased at the rate of $6$% p.a. Find the population at the end of the year $2008$

Answer 1

Year $2006$- Population is $150000$

Increased at the rate at $6\%p.a.$

After year $2008$ population will be say $x$

$x=150000{(1+\frac{6}{100})}^{2008-2006}$

$x=150000(1.06{)}^2$

$x=168540$

After year $2008$ population will be $168540$.